PLEASE SOLVE " dy/dx=sin(x+y)+cos(x+y) "
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Actually Welcome to the Concept of the Differential Equations,
Basically here we are going to use the Substitution as
x+y = p
thus we get as
1+dy/dx = dp/dx
dy/dx = dp/dx - 1
so we get as
dp/dx -1 = sinp + cosp
dp/dx = sinp + cosp +1
dp/ sinp + cosp + 1 = dx
integration on both sides we get as
lnl 1+tan(p/2)l = x + C
so we get as
ln l 1+tan(x+y/2) l = x+ C
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