Question

Please solve fast......

Answer 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

200-2|2x+1=0

2|2x+1=0

2x+1=0

2x=-1

x=-1/2 ra

Answer 2

†Given:

If 20 = 2+√3

†To find:

20³ +1/20³........,.....,...........(1)

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★Solution★

20 =2+√3

$\frac{1}{20} = \frac{1}{2 + \sqrt{3} }$

On rationalizing the denominator we get,

$\frac{1}{20} = \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} }$

By using the identity;

(x+y)(x-y) =x² - y²

$\frac{1}{20} = \frac{2 - \sqrt{3} }{ {2}^{2} - ( \sqrt{3 {}^){2} } } \\ \frac{1}{20} = \frac{2 - \sqrt{3} }{4 - 3} \\ \frac{1}{20} = 2 - \sqrt{3}$

So, putting the value in eq.(1)

$20 - \frac{1}{20} = (2 + \sqrt{3} ) - (2 - \sqrt{3)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 + \sqrt{3} - 2 + \sqrt{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{3} + \sqrt{3} = \red{2 \sqrt{3} }$

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Hope it helps you!!✨