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Angle CBD is 140 degrees
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angle abc will be 80 degree as its a cyclic quadrilateral it is not given but its true as all its vertices touch the circle therefore the angle cbd will be also 100 degree as its a linear pair.
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Answered by
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<AOC = 2<APC
100°= 2 * <APC {ANGLE formed by a chord at center is equal to 2* angle formed at remaining part of circle. Here the chord will be AC}
<APC = 50°
We know that exterior angle to a cyclic quadrilateral is equally the interior opposite angle
which in this case is <CBD
Therefore <CBD = <APC =50°
Hope it helps you
100°= 2 * <APC {ANGLE formed by a chord at center is equal to 2* angle formed at remaining part of circle. Here the chord will be AC}
<APC = 50°
We know that exterior angle to a cyclic quadrilateral is equally the interior opposite angle
which in this case is <CBD
Therefore <CBD = <APC =50°
Hope it helps you
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