please solve fast.......
Attachments:
Answers
Answered by
0
here's your answer
hope it will help you...
hope it will help you...
Attachments:
Answered by
0
Answer:
sec²θ * cosec²θ = sec²θ + cosec²θ
Step-by-step explanation:
LHS:
Given Equation is sec²θ * cosec²θ
= (1/cos²θ) * (1/sin²θ)
= (1)/(cos²θ * sin²θ)
∴ sin²θ + cos²θ = 1
= (sin²θ + cos²θ)/(cos²θ * sin²θ)
= (1/cos²θ) + (1/sin²θ)
= sec²θ + cosec²θ
= RHS
Hope it helps!
Similar questions