Math, asked by bhavyapatel49, 1 year ago

please solve fast.......

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Answers

Answered by UtkarshSrivastav
0
here's your answer
hope it will help you...
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Answered by siddhartharao77
0

Answer:

sec²θ * cosec²θ = sec²θ + cosec²θ

Step-by-step explanation:

LHS:

Given Equation is sec²θ * cosec²θ

= (1/cos²θ) * (1/sin²θ)

= (1)/(cos²θ * sin²θ)

sin²θ + cos²θ = 1

= (sin²θ + cos²θ)/(cos²θ * sin²θ)

= (1/cos²θ) + (1/sin²θ)

= sec²θ + cosec²θ

= RHS


Hope it helps!

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