Question

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Answer 1

To Prove : tan(90-A)× cotA -cos²A   =0

                          cosec²A

Proof : cotA× cotA/cosec²A - cos²A                 {∵tan(90-A) = cotA}

           cot²A/cosec²A - cos²A

          cos²A/sin²A×1/cosec²A - cos²A             {∵cot²A = cos²A/sin²A }

          cos²A - cos²A

         = 0

Hence Proved

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Answer 2

Answer:

I got till this next you do