Question

please solve fast. fast​

Answer 1

My answer is letter B

Step-by-step explanation:

You multiply it

Answer 2

$\huge \sf{f(x) = 0}$

$\sf{f(x) = 6 {x}^{3} - {11x}^{3} + kx - 20 }$

$\tt5 {x}^{3} + kx - 20 = 0$

$\tt \bigstar \: {let \: us \: substute \: the \: value \: of \: (x)}$

$\tt5 \times { (\dfrac{4}{3} ) }^{3} - k \times \dfrac{4}{3} = 20$

$\sf5 \times \dfrac{125}{64} + k \times \dfrac{5}{4} = 20$

$\sf \frac{625}{27} - k \times = \not20 \times \dfrac{3} { \not4}$

$\tt \dfrac{625}{27} - k = 15$

$\tt{k = \frac{625}{27} - 15 }$