please solve fast from image attached
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x=30°,y=60°,z=90°
Angle DCX= Angle ADC+AngleDAC. [ In triangle exterior angle is equal to sum of the opposite interior angle ]
120°=X+90°
X°=120°-90°
X°=30°
In ∆ ADC [angle sum property]
90°+X°+Y°=180°
90°+30°+Y°=180°
Y°=180°-120°
Y°=60°
Now In ∆ ABC
X°+Y°+Z°=180°
30°+60°+Z°=180°
Z°=180°-90°
Z°=90°
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