Question

please solve fast give me answer​

Answer 1

Given :-

Position of Particle = r = 3t i - 2t² j + 4k m.

Here, we are asked to find Velocity as well as Acceleration of particle at t = 2s.

In this question we will differentiate 'r' w.r.t dt in order to find Velocity and after finding velocity we will again differentiate to find the Acceleration of the particle.

v = dr/dt

v = d(3t i - 2t² j + 4k)/dt

v =3i - 4t j

Putting the value t = 2s

v = 3i - 8j

As this is in the vector form we will find resultant of both.

|V| = √ (3)² + (-8)²

|V| = √ 9 + 64

|V| = √73 ms-¹

Again, differentiating v w.r.t dt in order to find Acceleration.

a = dv/dt

a = d(3i - 4t j)/dt

a = 4 (-j) ms-².

Hence,

The Velocity of particle = V = √73 ms-¹

The Acceleration of particle = a = 4 (-j) ms-².