Question

please solve fast is aurgent ​

Answer 1

Step-by-step explanation:

1. dy/dx = 2x+5
2. dy/dx = cos(e^2x ) .e^2x .2 = 2e^2x cose^2

4.dy/dx= e^2Q

5. dy/dx = 0

6.dy/dx = 2ax + bsinx + c/x

7. dy/dx = 10( 2x-5)⁹.2

dy/dx = 20 (2x-5)⁹

8.taking log both sides

log y =x³loge

1/y dy/dx =x³ .1 -loge.3x²

dy/dx = y(x³-3x²loge)

dy/dx= x²e^x³ (x-3loge)