Question

please solve fast . it's very urgent .. best answer I will make brainlist

Answer 1

25 mL of 0.75 M HCl = 25 x 0.75 / 1000 moles

= 0.01875 moles

1 mole of HCl need 1/2 mole of CaCO3

0.01875 moles of HCl need 0.01875/2 = 0.00937 moles of CaCO3

mass of 0.00937 moles of CaCO3 = 0.00937 x 100 = 0.937 g

Mass of CaCO3 required is 0.937 g