Question

PLEASE SOLVE FAST IT VERY IMPORTANT!!DONT JOKE OR GIVE FALSE ANSWER.
A cricket ball of mass 70g moving with a velocity of 0.5 m/s is stopped by a player in 0.5s. What is force applied by the player to stop the ball?

Answer 1

mass of ball = 70g = 0.07 kg
vilocity of ball , u = 0.5 m/sec
time = 0.5 s
final vilocity of ball = 0 m/sec
force = mass (vilocity - u /time)
0.07 (0 - 0.5 /0.5)
-0.07 newton

Answer 2

m= 0.07kg
u=0.5m/s ,v= 0
t=0.5sec
F= ma
a=-0.5/0.5=-1m/s^2
F= -0.07N