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Given that, ∆QOR ~ ∆POS
Then, OQ/OP = OS/OR = PS/QR
Since PQRS is a trazepium, QS and PR are diagonals of PQRS.
Diagonals meet at bisection.
Which means OQ = OS, OP = OR
=> OQ/OS = 1
OP/OR = 1
Therefore, OQ/OP = OS/OR = PS/QR = 1
=> PS/QR = 1
or PS = QR
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