Question

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Answer 1

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies \sf \triangle\:ABC=\triangle PQR\\ \\ \implies \sf \frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{AR}\\ \\ \frac{AB}{PQ}=\frac{2BD}{2QM}\:\:\:\:\:\:[AD\: and\: PM\: are\: medians]$

$\implies \sf \frac{AB}{PQ}=\frac{BD}{QM}$                         (1)

$\implies \sf In\: \triangle ABD\: and\: \triangle PQM$

$\sf \frac{AB}{PQ}=\frac {BD}{QM}$

$\sf \angle B=\angle Q$

$\sf Therefore \:\triangle ABC=\: \triangle PQR$