Math, asked by sss7893, 8 hours ago

please solve fast please​

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Answered by abhijay1705
0

Answer:

-b/c is the answer.

Step-by-step explanation:

sum of roots = coefficient of x/coefficient of x²

given: p and q are roots of the equation

p+q=-b/c

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Answered by brokendreams
0

The answer of this question is p+q=\frac{b}{a}.

Step-by-step explanation:

We are given with a quadratic equation having roots p and q,

ax^{2} -bx+c=0

and we have to find the sum of p and q or we can say the sum of roots.

  • Formula used,

If we have general form of quadratic equation such as,

ax^{2} +bx+c=0

then sum of roots is the fraction of (-coefficient of x) to the (coefficient of x^{2} ) or sum of roots =\frac{-b}{a}.

  • Calculation for sum of p and q,

In the given quadratic equation

ax^{2} -bx+c=0

we have coefficient of x is '-b' and coefficient of x^{2} is 'a' so the sum of roots is,

p+q=\frac{-(-b)}{a})

         =\frac{b}{a}

So the sum of p and q is \frac{b}{a}.

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