Question

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Answer 1

Step-by-step explanation:

Given,

A2+B2+c2-ab-bc-ca

Multiphy and divide by 2

=22×(a2+b2+c2−ab−bc−ca)

=2a2−2ab+b2+b2−2bc+c2+c2−2ac+a2

=2(a−b)2+(b−c)2+(c−a)2

square of a number is always greater than or equal to zero.

∴(a−b)2+(b−c)2+(c−a)2≥0

and

(a−b)2+(b−c)2+(c−a)2=0 when a=b=c

Hence, a2+b2+c2−ab−bc−ca is always non negative