Question

Please solve... Fgjgffdhjkvddfghhjkjvhh

Answer 1

heya...!!!


$\frac{sin \alpha }{sec \alpha + tan \alpha - 1 } + \frac{cos \alpha }{cosec \alpha + cot \alpha - 1} \\ \\ = > \frac{sin \alpha }{ \frac{1}{cos \alpha } + \frac{sin \alpha }{ cos \alpha } - 1 } + \frac{cos \alpha }{ \frac{1}{sin \alpha } + \frac{cos \alpha }{sin \alpha } - 1 } \\ \\ = > \frac{sin \alpha }{ \frac{1 + sin \alpha - cos \alpha }{cos \alpha } } + \frac{cos \alpha }{ \frac{1 + cos \alpha - sin \alpha }{sin \alpha } } \\ \\ = > \frac{sin \alpha cos \alpha }{1 + sin \alpha - cos \alpha} + \frac{sin \alpha cos \alpha }{1 + cos \alpha - sin \alpha } \\ \\ = > \frac{sin \alpha cosa(1 + cos \alpha - sin \alpha + 1 +sin \alpha - cos \alpha ) }{(1 + sin \alpha - cos \alpha )(1 + cos \alpha - sin \alpha )} \\ \\ = > \frac{sin \alpha cos \alpha \times 2}{1 + cos \alpha - sin \alpha + sin \alpha + sin \alpha cos \alpha - {sin}^{2} \alpha - cos \alpha - {cos}^{2} \alpha + cos \alpha si n\alpha } \\ \\ = > \frac{sin \alpha cos \alpha \times 2}{1 - {sin}^{2} \alpha - {cos}^{2} \alpha + 2sin \alpha cos \alpha } \\ \\ = > \frac{2sin \alpha cos \alpha }{1 - ( {cos}^{2} \alpha + {sin}^{2} \alpha ) + 2sin \alpha cos \alpha } \\ \\ = > \frac{2sin \alpha cos \alpha }{1 - 1 + 2sin \alpha cos \alpha } \\ \\ = > \frac{2sin \alpha cos \alpha }{2sin \alpha cos \alpha } = 1$