Question

please solve guys pls kardoo pls yaar help me na dont neglect​

Answer 1

hope it is help full to you

Answer 2

Answer:

Explanation:

Q1)

Q2)

PO = RO

∠P = ∠S

∠POQ=∠ROS( vertically opposite angles)

∴∧POQ≅∧ROS(ASA THEORY)

Q3)

∠BLC=∠BMC (90°)

∠MBC=∠BCL

BC=BC(same base)

∧MBC≅∧BCL(AAS)  

∴BL=CM

Q4)

BA=CA

BD=CD

AD=AD(SAME BASE)

∧ABD≅∧ACB

⇒∠A=∠B

∴AD bisects ∠A and ∠D

I couldn’t solve the first question but pls mark as brainliest