Please solve. I have exam tomorrow. Please i beg of you
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WE PROVE ANGLE A BISECT BC
SO,
IN ΔABD = ACD
==> AD = AD (COMMON)
==> ∠ADB = ∠ADC (EACH 90°)
AB = AC (GIVEN)
BY SAS CONGRUENCE RULE
ΔABD = ΔACD
SO, BY CPCT
∠BAD = ∠BAC
SO, ∠A BISECT BC
Smartguy123:
I hope I can trust you
Can I
YA
I just figured out
I can't trust you
It's by RHS not SAS
Sorry but your answer is wrong
OOH SRY YES I DO NOT THINK YOU ARE RIGHT ITS RHS RULE
I DO NOT THINK
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