Question

PLEASE SOLVE..
I WANT SOLUTION WITH EXPLANATION
The lower part of circus tent is a right circular cylinder and the upper part is right circular cone. The diameter of the Base of tent is 56m and height of the cone is 15m . The total height of the tent is 60m . How many square metres of canvas is required for the tent ? Find the volume of the air space in tent.
$(\pi = \frac{22}{7} )$
Answer is 7304 sq. cm and 73920 cube. cm

Answer 1

ĀNSWĒR ⬆⬆⬆

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Answer 2

Okay so after examining this question for a long time I get to know about a minute mistake....
Here you mentioned that 15 m is the height of cone but the answer you are asking for can be derived by taking 15 m as the height of cylinder..... Let's figure it out.... So these photos are showing you that how can we solve it by taking 15 m as the height of the cone!!
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And if you take 15 m as the height of cylinder then you'll get the right answer which is you asking for...
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Solution :-

Radius of the base = Diameter/2

⇒ 56/2 = 28 m

Height of the cylindrical part = 15 m

Curved Surface Area of Cylinder = 2πrh

⇒ 2*22/7*28*15

= 2640 m²

Curved Surface Area of Cone = πrl

To find the Curved Surface Area of Cone, first we have to calculate the slant height of cone.

Slant Height of Cone = l = √r² + h²

⇒ √28² + 45²

⇒ √784 + 2025

⇒ √2809

⇒ Slant height of cone = 53 m

Curved Surface Area of Cone = πrl

⇒ 22/7*28*53

= 4664 m²

Total area of the cylindrical part and the conical part = 2640 + 4664 

= 7304 m²

So, the area of the canvas required is 7304 m²

Answer.
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