Question

please solve I will mark brainliest​

Answer 1

The answer is 1.. The first one was wrong

Answer 2

Answer:

Let:

=> $\tt{\sqrt{6 \sqrt{6 \sqrt{6 \sqrt{6 ...}}}} = x}$

Squaring on both sides, we get:

=> $\tt{6 \sqrt{6 \sqrt{6 \sqrt{6 \sqrt{6 ...}}}} = x^{2}}$

We know that:

$\tt{\sqrt{6 \sqrt{6 \sqrt{6 \sqrt{6 ...}}}} = x}$

Thus we get:

=> $\tt{6x = x^{2}}$

Both sides "x", cancelled:

=> x = 6

Thus, $\tt{\sqrt{6 \sqrt{6 \sqrt{6 \sqrt{6 ...}}}} = 6}$

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