Question

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Answer 1

Answer:

Quantity of lead in 50 kg of alloy = 60% of 50 kg = (50 × 60 )kg = 30 kg.

100

Let the required quantity of lead to be added be x kg.

Then, weight of lead = (30 + x) kg.

And, weight of new alloy = (50 + x) kg.

Percentage of lead in new alloy = (30+x) %

( 50+x)

∴ 30+x ×100=75

50+x

⇒ 30+x =3

50+x 4

⇒ 4(30 + x) = 3(50 + x)

⇒ 120 + 4x = 150 + 3x

⇒ 4x - 3x = 150 - 120

⇒ x = 30