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Let B and C be the vertex having exterior angles 104 and 136
respectively.
Ext∠B=104 °
and Ext∠C=136 °
Using theorem "Exterior angle is the sum of interior opposite angles", we get
∠A+∠B=104°.......... (1)
∠A+∠C=136° .......... (2)
Adding equation (1) and (2)
∠A+∠B+∠C=240°
As we know, ∠A+∠B+∠C=180°
Hence,
∠A=240 °−180° =60 °
From equation (1),
∠B=104° −60° =44°
From equation (2),
∠C=136° −60° =76°
Hence, angles of the triangle are ∠A=60° ∠B=44° and ∠C=76°
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