Question

please solve if Cos ( a - b) sin ( c + d ) = cos ( a + b ) sin ( c - d) then prove - ( cot a cot b cot c ) = cot d
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Answer 1

Step-by-step explanation:

● Sol : - Upar h

● I Hope you Understand!!!!!

Thank you!!!!

Answer 2

Step-by-step explanation:

cos(A+B)sin(C+D)=cos(A−B)sin(C−D)

**Shifting cos ( A- B ) and sin (C+D) **

cos(A+B)/cos(A−B)=sin(C−D)/sin(C+D)

** Adding cos(A+B) and subtracting cos(A−B) in L.H.S. and Adding sin(C−D) and subtracting sin(C+D) in R.H.S.**

cos(A+B)+cos(A−B)/cos(A+B)−cos(A−B)=sin(C−D)+sin(C+D)/sin(C−D)−sin(C+D)

** Solving equations on both the sides.**

(2cosAcosB)/-(2sinAsinB)=(2sinCcosD)/(2sinDcosC)

** Converting trignometric ratios into cot**

-cotAcotB=tanCcotD

- ( cot a cot b cot c )=cotD

HOPE THIS HELPS YOU.