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If x^3+px^2+qx+6 leaves reminder 3 when divided by x-3 and leaves zero when divided by x-2.Find the value of p and q.
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Answered by
3
using remainder theorem
1) 3^3 + 9p +3q+6= 3
2) 2^3 +4p+ 2q +6 =0
So,
p= -3, q= -1
1) 3^3 + 9p +3q+6= 3
2) 2^3 +4p+ 2q +6 =0
So,
p= -3, q= -1
Answered by
5
hope this will help you dear
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