Math, asked by raone03, 1 year ago

[Please Solve in Detail] Four persons started to do a work together. 'A' works only in starting two days after that B, C and D works alternately starting from B. Ratio of time taken by A, B, C and Dif they work alone is 4: 3: 2: 5. If the work is completed in 12 days then in how many days A and Ccan complete the work if they work together? (a) 6 days (b) 12 days (c) 10 days (d) 8 days (e) 4 days​

Answers

Answered by Agastya0606
0

Given: Four persons started to do a work together, 'A' works only in starting two days, B, C and D works alternately starting from B, time taken by A, B, C and D, if they work alone is 4: 3: 2: 5, work is completed in 12 days.

To find:  How many days A and C can complete the work if they work together.

Solution:

  • As we know that B worked for 4 days, C worked for 3 days,  D worked for three days,

                      So, the total days work done by a A is 2 days.

                      Similarly,  the total days work done by a B is 4+2= 6 days.

                      Similarly,  the total days work done by a C is 3+2= 5 days.

                      Similarly,  the total days work done by a D is 3+2= 5 days.

  • Now we have given the ratio of the time they have worked.
  • So, let the common ratio be x.
  • So their alone time of work to complete is 4x, 3x, 2x, 5x.
  • So now :

         2/2x + 6/3x + 5/2x + 5/5x = 1.

         by solving this, we get:

         x = 360/60 = 6

Answer:

                      So, the total days work done by a A is 4(6) = 24 days,  B is 3(6) = 18 days,  C is 2(6) = 12 days and D is 5(6) = 30 days.

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