Math, asked by unmonaneo, 5 hours ago

please solve in step by step​

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Answered by adiwan2
0

Step-by-step explanation:

  \frac{log(16)}{ log(9) }   \times  \frac{ log(10) }{ log(4) }   \times  \frac{ log(8) }{ log(10) }

 =  \frac{ log( {2}^{4} ) }{ log( {3}^{2} ) }  \times  \frac{ log( {2}^{3} ) }{ log(2^{2} ) }

 =  \frac{4 log(2) }{2 log(3) }  \times  \frac{ log(8) }{2 log(2) }

 =   \frac{ log(8) }{ log(3) }  =  log_{3}(8)

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