Question

Please solve is properly or else I will report you .

Answer 1

$\huge\bf\maltese{\underline{\red{Answer}}}\maltese$

Area of rectangle ABCD

A= L×B= 80×42= 3360 Cm²

Area of Figure 1=

$\frac{1}{2} \pi \: {r}^{2} = \frac{1}{2} \times \frac{22}{7} \times 21 \times 21 \\ = 11 \times 3 \times 21 = 693c {m}^{2}$

Area of figure 2= 693cm²

Area of whole figure= 3360+693+693= 4746 cm²

Perimeter of whole Figure= perimeter of rectangle+ perimeter of figure 1 + perimeter of figure 2

Perimeter of rectangle= 2(l+b)= 2(80+42)

=2×122= 244cm

Perimeter of figure 1= π r= 22/7× 21= 22×3= 66Cm

Perimeter of whole figure= 244+66+66= 376 Cm

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Answer 2

Answer:

Area of rectangle ABCD

A= L×B= 80×42= 3360 Cm²

Area of Figure 1=

\begin{gathered} \frac{1}{2} \pi \: {r}^{2} = \frac{1}{2} \times \frac{22}{7} \times 21 \times 21 \\ = 11 \times 3 \times 21 = 693c {m}^{2} \end{gathered}

2

1

πr

2

=

2

1

×

7

22

×21×21

=11×3×21=693cm

2

Area of figure 2= 693cm²

Area of whole figure= 3360+693+693= 4746 cm²

Perimeter of whole Figure= perimeter of rectangle+ perimeter of figure 1 + perimeter of figure 2

Perimeter of rectangle= 2(l+b)= 2(80+42)

=2×122= 244cm

Perimeter of figure 1= π r= 22/7× 21= 22×3= 66Cm

Perimeter of whole figure= 244+66+66= 376 Cm

Step-by-step explanation:

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