Question

Please solve it?????????????????????????​

Answer 1

Answer:

Hey mate here is your answer

Explanation:

AB:-

distsnce:-area of triangle ABF

:-1/2 × base × height

:-1/2×5×6

:-15 m

v:-6,u:-0

acceleration= v-u/t

=6-0/5=6/5 =1.2m/s^2

BC:-

Distance=area of rectangle BCEF

=L×B

=6×5

=30m

v=6,u=6

accelerations:-v-u/t=6-6/5=0m/s^2

CD:-

Distance:-area of triangle CDE

=1/2 × b ×h=1/2×6×5

=15m

v=0,u=6

accelerations:- v-u/t=0-6/5

=-1.2 m/s^2