Question

please solve it.....​

Answer 1

Answer:

$({x}^{3} + \frac{1}{ {x}})^{2} - 3(x + \frac{1}{x}) + (x + \frac{1}{2} {)}^{2} - 2 + x + \frac{1}{x} = 70 \\ (x + \frac{1}{x} {)}^{2} - (x + \frac{1}{x} {)}^{2} - 2(x + \frac{1}{x}) - 72 = 0 \\ (x + \frac{1}{x} - 4)((x + \frac{1}{x} {)}^{2} + 5(x + \frac{1}{x}) + 18) = 0 \\ (x + \frac{1}{x} - 4)((x + \frac{1}{x} + \frac{5}{2} {)}^{2} + \frac{47}{4})) = 0 \\ x + \frac{1}{x - 4 = 0} \: x + \frac{1}{x} = 4 \\ {x}^{2} + \frac{1}{ {x}^{2} } = (x + \frac{1}{x} {)}^{2} - 2 = 16 - 2 = 14 \\ {x}^{4} + \frac{1}{ {x}^{4} } = ( {x}^{2} + \frac{1}{ {x}^{2} } {)}^{2} = 196 - 2 = 194 \\ = {x}^{4} + \frac{1}{ {x}^{4} } = 194$

unblock me bhaiya plz :(

Answer 2

$\huge\mathcal\colorbox{lavender}{{\color{b}{✿Yøur-Añswer♡}}}$

$\large\bf{\underline{\red{VERIFIED✔}}}$

$</p><p>\begin{gathered} ({x}^{3} + \frac{1}{ {x}})^{2} - 3(x + \frac{1}{x}) + (x + \frac{1}{2} {)}^{2} - 2 + x + \frac{1}{x} = 70 \\ (x + \frac{1}{x} {)}^{2} - (x + \frac{1}{x} {)}^{2} - 2(x + \frac{1}{x}) - 72 = 0 \\ (x + \frac{1}{x} - 4)((x + \frac{1}{x} {)}^{2} + 5(x + \frac{1}{x}) + 18) = 0 \\ (x + \frac{1}{x} - 4)((x + \frac{1}{x} + \frac{5}{2} {)}^{2} + \frac{47}{4})) = 0 \\ x + \frac{1}{x - 4 = 0} \: x + \frac{1}{x} = 4 \\ {x}^{2} + \frac{1}{ {x}^{2} } = (x + \frac{1}{x} {)}^{2} - 2 = 16 - 2 = 14 \\ {x}^{4} + \frac{1}{ {x}^{4} } = ( {x}^{2} + \frac{1}{ {x}^{2} } {)}^{2} = 196 - 2 = 194 \\ = {x}^{4} + \frac{1}{ {x}^{4} } = 194 \end{gathered}$

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