Question

please solve it.....❤​

Answer 1

Mole fraction of solute in an aqueous solution is 0.2 molality of solution (if molar mass of solute is 40) will be. 

Answer 2

Given:

Mole fraction of glucose= 0.2

Molefraction of solution = 1

So, mole fraction of water= 1-0.2

= 0.8

Molality = moles of solute/ kg solvent

Molar mass H2O = 18 g/kg

Mass of H2O = (0.8×18)/1000

=0.014 kg

Molality = 0.2 / 0.014

= 14 M