Question

please solve it.......................​

Answer 1

Answer :-

$\mathsf{R=17.32N}$

Given:-

$F_1 = F_2 = 10 N \\ \theta = 60^{\circ}$

To find :-

The resultant vector.

Solution:-

• By using vector law of addition.

→$\mathsf{R = \sqrt{F_1^2 + F_2^2 + 2F_1.F_2 Cos \theta }}$

• Where $Cos\theta$ is the angle between two force.

• Put the given values,

→$\mathsf{R = \sqrt{(10)^2 +(10)^2 + 2 \times 10 \times 10 Cos60^{\circ}}}$

→$\mathsf{ R = \sqrt{100 + 100 + 200 \times \dfrac{1}{2}}}$

→$\mathsf{R = \sqrt{200 + 100}}$

→$\mathsf{R = \sqrt{300}}$

→$\mathsf{R = 17.32 N }$

hence,

The resultant force is $\mathsf{17.32N }$

Answer 2

Answer:

this is the answer of the question