Question

please solve it .........​

Answer 1

Answer:

x=±3 x=3 or x=-3

z=±1 z=1 or z=-1

Step-by-step explanation:

Answer 2

$\huge\bf\underline{\underline{Question:}}$

Find the positive value of variable for which the given equation is satisfied.

$(i) \frac{1 - {x}^{2} }{1 + {x}^{2} } = \frac{ - 4}{5} \\ \\ (ii) \frac{3 {z}^{2} + 7}{4 + {z}^{2} } = 2$

$\huge\bf\underline{\underline{Solution:}}$

$(i) \frac{1 - {x}^{2} }{1 + {x}^{2} } = \frac{ - 4}{5} \\ by \: cross \: multiplication \\ 5 - 5 {x}^{2} = - 4 - 4 {x}^{2} \\ 9 = {x}^{2} \\ x = \sqrt{9} \\ we \: need \: positive \: value \: of \: variable$

$\boxed{\red{x = 3}}$

$(ii)\frac{3 {z}^{2} + 7 }{4 + {z}^{2} } = 2 \\ by \: cross \: multiplication \\ 3 {z}^{2} + 7 = 8 + 2 {z}^{2} \\ {z}^{2} = 1 \\ z = \sqrt{1} \\ we \: need \: positive \: value \: of \: variable$

$\boxed{\red{z = 1}}$

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@ItsMysteriousGirl