please solve it................
Answers
Maximum velocity of the object will be At m/sec
Explanation:
We have that firstly the object starts from rest so its initial velocity will u = 0 m /sec
Its acceleration is Am/sec^2 and deceleration is Bm/sec^2'
As it is given that from rest its first accelerate and then decelerate so just before deceleration object will be at maximum speed
From first equation of motion we know that v = u+at
So v=0+At=Atm/sec
So maximum velocity of the object will be At m/sec
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Explanation:
Using
Distance traveled by the body in the first second=
=5 meters= S1
Distance traveled by the body in the second second= distance traveled by the body in two seconds- distance traveled by the body in one second
=
=20-5
=15 meters= S2
Distance traveled by the body in the third second= distance traveled by the body in three seconds- distance traveled by the body in two seconds
=
=45-20
=25 meters=S3
So, answer is.
S1 : S2 : S3 = 5 : 15 : 25
=> 1 : 3 : 5
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