Question

please solve it ............................................................

Answer 1

Answer:

-1 m/s²

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Answer 2

Given:-

☛Final velocity= 0m/s

☛Initial velocity= 72km/h

☛Distance covered = 200m

   

Find:-

☛Retardation-?

   

Formula to be used:-

$\sf{v^2-u^2=2as}$

where,

v= final velocity

u=initial velocity

a=acceleration(-retardation)

s= distance covered

   

Solution:-

 

First Change km/h to m/s

we know,

1km=1000m

1hr= 3600sec

$\sf{so, \dfrac{1km}{1hr} = \dfrac{1000m}{3600s} = \dfrac{5m}{18s} }$

$\sf{1km/h =\dfrac{5}{18} \times 72= 20m/s}$

Initial velocity = 20m/s

 

Using 3rd equation of motion,

$\sf{v^2-u^2=2as}$

$\sf{\implies 0^2 -20^2= 2\times a \times 200}$

$\sf{\implies -400 = 400\times a}$

$\sf{\implies a= \dfrac{-400}{400} = -1m/s^2 }$

   

Therefore, Retardation produces is -1m/s².