Physics, asked by noahjames123, 11 months ago

please solve it ............................................................

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Answers

Answered by param511
0

Answer:

-1 m/s²

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Answered by LoverLoser
2

Given:-

☛Final velocity= 0m/s

☛Initial velocity= 72km/h

☛Distance covered = 200m

   

Find:-

☛Retardation-?

   

Formula to be used:-

\sf{v^2-u^2=2as}

where,

v= final velocity

u=initial velocity

a=acceleration(-retardation)

s= distance covered

   

Solution:-

 

First Change km/h to m/s

we know,

1km=1000m

1hr= 3600sec

\sf{so, \dfrac{1km}{1hr} = \dfrac{1000m}{3600s} = \dfrac{5m}{18s} }

\sf{1km/h =\dfrac{5}{18} \times 72= 20m/s}

Initial velocity = 20m/s

 

Using 3rd equation of motion,

\sf{v^2-u^2=2as}

\sf{\implies 0^2 -20^2= 2\times a \times 200}

\sf{\implies -400 = 400\times a}

\sf{\implies a= \dfrac{-400}{400} = -1m/s^2 }

   

Therefore, Retardation produces is -1m/s².

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