Question

please solve it ☺☺............

Answer 1

Hey mate here is your answer....
.......☆☆☆■■■■
4x²-4a²x+(a⁴-b⁴)=0 or,
4x²- 2{(a²+b²)+(a²-b²)}x+(a²+b²)(a²-b²)=0
or, 4x²-2( a²+b²)x-2(a²-b²)x+(a²+b²)(a²-b²)=0
the solution for a in this can't be determined...
......

Answer 2

Hi ,

4x²- 4a²x + a⁴ - b⁴ = 0

4x² - 4a²x + ( a² )² - ( b² )² = 0

4x² - 4a²x + ( a² + b² ) ( a² - b² ) = 0

4x² - 2( a² + b² )x - 2( a² - b² )x +(a² + b² )( a² - b² ) =0

2x[ 2x-( a² + b²] - (a²-b²)[2x- (a²+b²)]=0

[ 2x-(a² + b² )] [ 2x - ( a² - b² ) ] = 0

Therefore ,

2x - ( a² + b² ) = 0 or 2x - ( a² - b² ) = 0

2x = ( a² + b² ) or 2x = ( a² - b² )

x = ( a² + b² )/2 or x = ( a² - b² )/2

I hope this helps you.

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