Math, asked by Lovelit, 1 day ago

please solve it.

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Answered by itzbabygirl123

4

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effective length of the rod that create the EMF due to z component of the field l=5sin53=4m

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32effective length of the rod that create the EMF due to y component of the field l=0 m

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32effective length of the rod that create the EMF due to y component of the field l=0 mE

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32effective length of the rod that create the EMF due to y component of the field l=0 mE y

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32effective length of the rod that create the EMF due to y component of the field l=0 mE y

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32effective length of the rod that create the EMF due to y component of the field l=0 mE y =3∗2∗0=0

effective length of the rod that create the EMF due to z component of the field l=5sin53=4mE z =4∗2∗4=32effective length of the rod that create the EMF due to y component of the field l=0 mE y =3∗2∗0=0net EMF=32 volt

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