Question

please solve it !!!​

Answer 1

Answer:

In ∆ AQC and ∆APB

AQ=AP (a is the mid point )

AC=AB (sides of ∆ ABC)

L ABP=L ACQ (angle of triangle)

So ∆ AQC =~∆ APB (By sas congrace rule)

Then, ar∆AQC=ar∆APB( BY CPCT)