Question

please solve it and ​

Answer 1

${}^{4} \sqrt{28} \div {}^{3} \sqrt{7}$

$=> \frac{ {}^{4} \sqrt{28} }{ {}^{3} \sqrt{7} } = > \frac{4}{3} \sqrt{ \frac{ \cancel{28}}{ \cancel{7} } }$

$= > \frac{4}{3} \sqrt{4}$

$=> \frac{4}{3} \cancel{{ \sqrt{} {2}^{2} }} \\ = > \frac{4}{3} \times 2 \\ = \frac{8}{3}$

so, answer is

$\boxed{ \frac{8}{3}}$