Question

please solve it,and answer will be in exponential form​

Answer 1

Step-by-step explanation:

$((2) {}^{ - 2} + (4) {}^{ - 1} \div (3) {}^{1}) {}^{ - 1} \\ = ( \frac{1}{4} + \frac{1}{4} \times \frac{1}{3} ) {}^{ - 1} \\ = ( \frac{1}{4} + \frac{1}{12} ) {}^{ - 1} \\ = ( \frac{3 + 1}{12} ) {}^{ - 1} \\ = ( \frac{4}{12} ) {}^{ - 1} \\ = ( \frac{1}{3} ) {}^{ - 1} = 3 \: \: ans$

Hey! Mate Here is your solution. Thanks