Question

please solve it and explain to irrelevant anwers will be reported​

Answer 1

$\huge\mathbb\pink{Answer}$

A can do 1/5th of work in 2 days.

This implies that the total work is done by A in 2× 5 = 10 days

A's one day work = $\frac{1}{12}$

B can do $\frac{2}{3}$ rd work in 8 days

This implies that the total work is done by B in = 8 × $\frac{3}{2}$= 12 days

B's one day work = $\frac{1}{12}$

Now, (A+B)'s one day work = $\frac{1}{10}$

+ $\frac{1}{12}$

=> 6 + $\frac{5}{60}$

=> $\frac{11}{60}$

If A and B 's one day work = $\frac{11}{60}$

They can complete the work together in = $\frac{60}{11}$ days

=> 5 whole $\frac{5}{11}$days

OR

=> $\frac{60}{11}$days.