Question

please solve it as fast as posssible

Answer 1

Answer:

Value of expression = 1.

Step-by-step explanation:

Given expression is ;

                   ⇒   $\frac{(32)^{0.2} +(81)^{0.25} }{(256)^{0.5}- (121)^{0.5} }$

                   ⇒   $\frac{(32)^\frac{2}{10} +(81)^\frac{25}{100} }{(256)^\frac{5}{10} - (121)^\frac{5}{10} }$

                   ⇒  $\frac{(2^{5} )^\frac{2}{10} +(3^{4} )^\frac{25}{100} }{(16^{2} )^\frac{5}{10} - (11^{2} )^\frac{5}{10} }$

                   ⇒  $\frac{(2)^{5*\frac{2}{10}} +(3)^{4*\frac{25}{100}} }{(16)^{2*\frac{5}{10}} - (11)^{2*\frac{5}{10}} }$

                   ⇒   $\frac{(2)^{\frac{10}{10}} +(3)^{\frac{100}{100}} }{(16)^{\frac{10}{10}} - (11)^{\frac{10}{10}} }$

                   ⇒  $\frac{(2) +(3)}{(16) - (11) }$   ⇒  $\frac{5}{5}$ = 1

Therefore, value of $\frac{(32)^{0.2} +(81)^{0.25} }{(256)^{0.5}- (121)^{0.5} }$ = 1 .