Math, asked by mjunaidalam699, 9 months ago

please solve it as soon as possible ​

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Answers

Answered by karthikdisley74
1

Step-by-step explanation:

  1. first arrange the variables in an order of a , b, c.
  2. then solve as the problem is given

(I) 6a+9b-4c

(ii)12a+5b+16c

(iii)6a+17b+23c

(iv)-45a-32b-61c

Answered by Preranaa
0

Answer:

(i) x+y+z

= 6a+8b+9c +2b-3a-6c +c -b+3a

= 6a+9b+4c

(ii) x-y+z

=6a+8b+9c-(2b-3a-6c)+c -b+3a

=6a+8b+9c-2b+3a+6c+c -b+3a

=12a+5b+14c

(iii) 2x-y-3z

= 12a+16b+18c-2b+3a+6c-3c+3b-9a

= 6a+11b+31c

(iv) 3y-2z-5x

= 6b-9a-18c-2c+2b-6a-30a-40b-45c

= 32b-65c-45a

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