Question

please solve it as soon as possible

Answer 1

to prove this question the figure is must, I think figure is... (in attachment)

hai mate,
here is your answer...

D is the mid point of BC and AE⊥BC.
In right ∆ ABE,
AB^2 = AE^2 + BE^2 … (1) (Pythagoras Theorem)
In right ∆ ADE,
AD^2 = AE^2 + ED^2 … (2) (Pythagoras Theorem)
From (1) and (2), we get

.......[ plz check attachment ]......

Since, AB= c, AD= p, BC = a, DE = x ……………….(Given)
Substituting the above values, we get

${c}^{2} = {p}^{2} - ax + \frac{ {a}^{2} }{4}$
hai mate...

i have given first questions answer in attachment...

if you add first and second questions answer, you will get theird one...

hope u can understand......
thank you