Question

Please solve it, ASAP.

Answer 1

Answer:

The answer to this question is 2

Step-by-step explanation:

We know

$\sin{0} =1 ,\sin{\frac{\pi}{6}} = \frac{1}{2}, \sin{\frac{\pi}{3}} = \frac{\sqrt{3}}{2} \text{ and }\sin{\frac{\pi}{2}} = 1$

Therefore,

$\sin^{2}{0} + \sin^{2}{\frac{\pi}{6}} + \sin^{2}{\frac{\pi}{3}} + \sin^{2}{\frac{\pi}{2}} \\= 0 + \frac{1}{4} + \frac{3}{4} +1 =2$