Question

Please Solve it...... BODMAS.....#No Spamming......
$\frac{5}{24}\: of \: ( \frac{7}{15} \: + \frac{1}{3} ) \div ( \frac{5}{6} - \frac{3}{5}) + (2 \frac{1}{2} )$
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Answer 1

$\LARGE{ \underline{ \pink{ \sf{Required \: answer:}}}}$

We have to solve the above by using the BODMAS rule which means:

• B = Brackets
• O = of
• D = Division
• M = Multiplication
• A = Addition
• S = Subtraction

━━━━━━━━━━━━━━━━━━━━

To solve:

• $\sf{ \dfrac{5}{24}\: of \: ( \dfrac{7}{15} \: + \dfrac{1}{3} ) \div ( \dfrac{5}{6} - \dfrac{3}{5}) + (2 \dfrac{1}{2} )}$

According to BODMAS rule, Brackets comes first. So, we need to compute the sums inside the brackets first.

⇛ $\sf{ \dfrac{5}{24}\: of \: ( \dfrac{7 + 5}{15} ) \div ( \dfrac{25 - 18}{30}) + \dfrac{5}{2} }$

On further calculation,

⇛ $\sf{ \dfrac{5}{24}\: of \: \dfrac{12}{15} \div \dfrac{7}{30} + \dfrac{5}{2} }$

Now it's time for solving the OF part, because it comes second in the BODMAS rule,

⇛ $\sf{ \dfrac{5}{24} \times \dfrac{12}{15} \div \dfrac{7}{30} + \dfrac{5}{2} }$

This is equals to,

⇛ $\sf{ \dfrac{1}{6} \div \dfrac{7}{30} + \dfrac{5}{2} }$

Now computing the division because it comes third,

⇛ $\sf{ \dfrac{1}{6} \times \dfrac{30}{7} + \dfrac{5}{2} }$

⇛ $\sf{ \dfrac{5}{7} + \dfrac{5}{2} }$

Finally addition,

⇛ $\sf{ \dfrac{10 + 35}{14} }$

And this is equals to,

$\therefore{\boxed{ \sf{ \frac{45}{14} = 3 \frac{3}{14} }}}$

And we are done !!

Answer 2

Step-by-step explanation:

Answer : -

= 5/24 × 7/15 + 1/3 ÷ 5/6 - 3/5 + 5/2

= 5/24 × ( 7 + 5 ) / 15 ÷ 5/6 ( - 6 + 25 ) /2

= 5/24 × ( 12 / 15 ) ÷ 5/6 + 19 / 2

= 1/ 6 ÷ 5 + 62/6

= 1 / 6 ÷ 67 / 6

= 1 / 6 × 6 / 67

= 6 / 402