please solve it by giving appropriate reason.
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3BaCl2 + 2Na3PO4 = Ba3(PO4)2 + 6NaCl
This is the balanced reaction
Now 3 moles of BaCl2 requires 2 moles of Na3PO4., i.e for every 1 mole of Na3PO4 we require 1.5 moles of BaCl2
Given 0.5 moles of BaCl2 and 0.2 moles of Na3PO4, i.e. 1 mole of of Na3PO4 has 2.5 moles of BaCl2. Hence Na3PO4 is a limiting reagent.
Now 2 moles of Na3PO4 gives 1 mole of Ba3(PO4)2, thus 0.2 moles will give 0.1 mole of Ba3(PO4)2.
Hence answer should be option D
This is the balanced reaction
Now 3 moles of BaCl2 requires 2 moles of Na3PO4., i.e for every 1 mole of Na3PO4 we require 1.5 moles of BaCl2
Given 0.5 moles of BaCl2 and 0.2 moles of Na3PO4, i.e. 1 mole of of Na3PO4 has 2.5 moles of BaCl2. Hence Na3PO4 is a limiting reagent.
Now 2 moles of Na3PO4 gives 1 mole of Ba3(PO4)2, thus 0.2 moles will give 0.1 mole of Ba3(PO4)2.
Hence answer should be option D
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