please solve it
Calculate the number of kj of heat necessary to raise the temperature of 60 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol-1 K-1.
please solve ??
Answers
Answered by
7
Answer : ----
➡No. of moles of Al (m) = (60g)/(27 g mol-1)
= 2.22 mol
➡Molar heat capacity (C) = 24 J mol-1 K-1.
➡Rise in temperature (∆T) = 55 – 35 = 20°C = 20 K
➡Heat evolved (q) = C x m x T
▶ = (24 ) x (2.22) x (20 K)
= 1065.6 J
= 1.067 kj
➡No. of moles of Al (m) = (60g)/(27 g mol-1)
= 2.22 mol
➡Molar heat capacity (C) = 24 J mol-1 K-1.
➡Rise in temperature (∆T) = 55 – 35 = 20°C = 20 K
➡Heat evolved (q) = C x m x T
▶ = (24 ) x (2.22) x (20 K)
= 1065.6 J
= 1.067 kj
aman4153:
thank you
1.066 .. its wrong dear
its 0.65 though .. leave it .. ^^"
Answered by
12
Given :
Δ T = 55°C - 35°C
= > Δ T = 20°C
Number of moles = mass / molar mass
= > n = 60 g / 27 g/moles
= > n = 2.22 moles
Q = m C Δ T
= Q = 2.22 × 24 × 20
= Q = 1065.6
= Q = 1.0656
= Q = 1.066 kJ
ANSWER :
1.066 is the required answer !
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