Question

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Answer 1

Step-by-step explanation:

Taking L.H.S

(1+tanA)^2 + (1-tanA)^2

By expanding,

1+ tan^2 A -2tanA + 1 + tan^2 +2tanA

1+tan^2A + 1+ tan^2A

we know,

sec^2A - tan^2A = 1

and by transposing

sec^2A = 1 + tan^2A

Now,

this means, by substituting  1 + tan^2A in place of sec^2A

we get

sec^2A + sec^2A

which is

2sec^2A

which is equal to R.H.S.

Hence proved!

Hope it helped.

Answer 2

Answer:

Step-by-step explanation: