Question

please solve it day after tomorrow is my exam

Answer 1

here is the answer. cube root of 5 into -11

Answer 2

●••••••• Hello Shreya •••••••●
《《Here is your answer》》
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$= 3 \sqrt[3]{40} - 4 \sqrt[3]{320} - \sqrt[3]{5} \\ \\ = 3 \sqrt[3]{8 \times 5} - 4 \sqrt[3]{8 \times 8 \times 5} - \sqrt[3]{5} \\ \\ = 3 \sqrt[3]{ {2}^{3} \times 5} - 4 \sqrt[3]{ {2}^{3} \times {2}^{3} \times 5} - \sqrt[3]{5} \\ \\ =3 \times 2 \sqrt[3]{5} - 4 \times 2 \times 2 \sqrt[3]{5} - \sqrt[3]{5} \\ \\ = 6 \sqrt[3]{5} - 16 \sqrt[3]{5} - \sqrt[3]{5} \\ \\ = - 10 \sqrt[3]{5} - \sqrt[3]{5} \\ \\ = - 11 \sqrt[3]{5}$
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