Question

please solve it fast​

Answer 1

Answer:

I hope its help you....

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Answer 2

Answer:

(eˣ/x + 1) + C

Step-by-step explanation:

$Given : \int \frac{xe^x}{(1 + x)^2} dx$

$\Rightarrow \int \frac{(x + 1 - 1)}{(x + 1)^2} e^x$

$\Rightarrow \int e^x[\frac{1}{x + 1} - \frac{1}{(x + 1)^2}]$

Since,integral eˣ[ f (x)+ f '(x) ] dx = eˣ f (x) + C

$\Rightarrow \boxed{\frac{e^x}{x + 1} + C}$

Hope it helps!